int s1,s2,s3;
double result = (s1+s2+s3)/3;
/
double result = (s1+s2+s3)/3.0;
double sum = s1+s2+s3;
double result = sum /3 ;
本文共 173 字，大约阅读时间需要 1 分钟。
int s1,s2,s3;
double result = (s1+s2+s3)/3;
/
double result = (s1+s2+s3)/3.0;
double sum = s1+s2+s3;
double result = sum /3 ;
转载于:https://my.oschina.net/u/230229/blog/123827